Amps to kW

Amps (A) to Kilowatts (kW) calculator and how to calculate

Amps (A) to Kilowatts (kW) calculator

Current type:
Current in amps: A
Voltage in volts: V

Kilowatts: kW

Amps to kilowatts conversion

How to convert electric current in amps (A) to electric power in kilowatts (kW)

DC amps to kilowatts conversion

The power P, in kW is calculated by multiplying the voltage V in volts (V) by the phase current I, in amps (A) and then dividing the result by 1,000.

P(kW) = I(A) × V(V) / 1000

Therefore:

Kilowatts are calculated by multiplying the volts by amps and then dividing by 1,000.

Kilowatt = amp × volt / 1000

Or

kW = A × V / 1000

Example

Work out the power consumption in an electrical circuit where the voltage supply is 110V and the current is 2A.

Solution

P = I × V/1000

P = 2A × 110V / 1000 = 0.22kW

AC single phase amps to kilowatts conversion

Actual power P, in kilowatts is calculated by multiplying the phase current I in amps (A) by the power factor PF, multiplied by the RMS voltage V, in volts (V), and then dividing the result by 1,000.

P(kW) = PF × I(A) × V(V) / 1000

Therefore:

Kilo-watts = amps times volts times the power factor divided by 1,000.

Kilowatt = PF × amp × volt / 1000

Or

kW = PF × A × V / 1000

Example

Given that the phase current in a circuit is 4A, the power factor is 0.9 and the RMS voltage is 110V, calculate the actual power consumption in the circuit.

Solution

Power P = PF × I × V /1000

P = 0.9 × 4A × 110V / 1000 = 0.396kW

AC three phase amps to kilowatts conversion

Real Power P, in kilowatts in an AC 3 phase circuit is calculated by multiplying the square root of 3 by the phase current I, in amps (A) multiplied by the power factor PF, multiplied by the line in line RMS VL-L voltage, in volts (V), and the dividing the result by 1,000.

P(kW) = 3 × PF × I(A) × VL-L(V) / 1000

Therefore;

Kilowatts = the square root of 3 times volts times the power facto divided by 1,000

Kilowatt = 3 × PF × amp × volt / 1000

Or

kW = 3 × PF × A × V / 1000

Example

Calculate the power consumption by an electrical appliance, given that its RMS voltage is 110V, its phase current is 4A and that the power factor is 0.9.

Solution

P = 3 × PF × V × I /1,000

P = √3 × 0.9 × 4A × 110V / 1000 = 0.685kW